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qapi: Merge UserDefTwo and UserDefNested in tests

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In the testsuite, UserDefTwo and UserDefNested were identical
structs other than the member names.  Reduce code duplication by
having just one type, and choose names that also favor reuse.
This will also make it easier for a later patch to get rid of
inline nested types in QAPI.  When touching code related to
allocations, convert g_malloc0(sizeof(Type)) to the more typesafe
g_new0(Type, 1).

Ensure that 'make check-qapi-schema check-unit' still passes.

Signed-off-by: Eric Blake <eblake@redhat.com>
Reviewed-by: Markus Armbruster <armbru@redhat.com>
Signed-off-by: Markus Armbruster <armbru@redhat.com>
This commit is contained in:
Eric Blake 2015-05-04 09:05:29 -06:00 • committed by Markus Armbruster
parent 3e391d3556
commit b6fcf32d9b
7 changed files with 102 additions and 103 deletions
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17
tests/test-qmp-input-visitor.c
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@ -248,23 +248,26 @@ static void check_and_free_str(char *str, const char *cmp)
static void test_visitor_in_struct_nested(TestInputVisitorData *data,
const void *unused)
{
UserDefNested *udp = NULL;
UserDefTwo *udp = NULL;
Error *err = NULL;
Visitor *v;
v = visitor_input_test_init(data, "{ 'string0': 'string0', 'dict1': { 'string1': 'string1', 'dict2': { 'userdef1': { 'integer': 42, 'string': 'string' }, 'string2': 'string2'}}}");
v = visitor_input_test_init(data, "{ 'string0': 'string0', "
"'dict1': { 'string1': 'string1', "
"'dict2': { 'userdef': { 'integer': 42, "
"'string': 'string' }, 'string': 'string2'}}}");
visit_type_UserDefNested(v, &udp, NULL, &err);
visit_type_UserDefTwo(v, &udp, NULL, &err);
g_assert(!err);
check_and_free_str(udp->string0, "string0");
check_and_free_str(udp->dict1.string1, "string1");
g_assert_cmpint(udp->dict1.dict2.userdef1->base->integer, ==, 42);
check_and_free_str(udp->dict1.dict2.userdef1->string, "string");
check_and_free_str(udp->dict1.dict2.string2, "string2");
g_assert_cmpint(udp->dict1.dict2.userdef->base->integer, ==, 42);
check_and_free_str(udp->dict1.dict2.userdef->string, "string");
check_and_free_str(udp->dict1.dict2.string, "string2");
g_assert(udp->dict1.has_dict3 == false);
g_free(udp->dict1.dict2.userdef1);
g_free(udp->dict1.dict2.userdef);
g_free(udp);
}