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memory: expose alignment used for allocating RAM as MemoryRegion API

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introduce memory_region_get_alignment() that returns
underlying memory block alignment or 0 if it's not
relevant/implemented for backend.

Signed-off-by: Igor Mammedov <imammedo@redhat.com>
Reviewed-by: Michael S. Tsirkin <mst@redhat.com>
Signed-off-by: Michael S. Tsirkin <mst@redhat.com>
This commit is contained in:
Igor Mammedov 2014-10-31 16:38:37 +00:00 • committed by Michael S. Tsirkin
parent 92a37a04d6
commit a2b257d621
8 changed files with 22 additions and 8 deletions
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2
include/exec/exec-all.h
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@ -333,7 +333,7 @@ extern uintptr_t tci_tb_ptr;
#if !defined(CONFIG_USER_ONLY)
void phys_mem_set_alloc(void *(*alloc)(size_t));
void phys_mem_set_alloc(void *(*alloc)(size_t, uint64_t *align));
struct MemoryRegion *iotlb_to_region(AddressSpace *as, hwaddr index);
bool io_mem_read(struct MemoryRegion *mr, hwaddr addr,