target/hppa: Make hppa_cpu_tlb_fill sysemu only

The fallback code in cpu_loop_exit_sigsegv is sufficient
for hppa linux-user.

Remove the code from cpu_loop that raised SIGSEGV.
This makes all of the code in mem_helper.c sysemu only,
so remove the ifdefs and move the file to hppa_softmmu_ss.

Reviewed-by: Philippe Mathieu-Daudé <f4bug@amsat.org>
Signed-off-by: Richard Henderson <richard.henderson@linaro.org>
This commit is contained in:
Richard Henderson 2021-09-14 16:39:34 -07:00
parent 70863887a8
commit 860e0b965b
5 changed files with 6 additions and 35 deletions

View file

@ -24,20 +24,6 @@
#include "hw/core/cpu.h"
#include "trace.h"
#ifdef CONFIG_USER_ONLY
bool hppa_cpu_tlb_fill(CPUState *cs, vaddr address, int size,
MMUAccessType access_type, int mmu_idx,
bool probe, uintptr_t retaddr)
{
HPPACPU *cpu = HPPA_CPU(cs);
/* ??? Test between data page fault and data memory protection trap,
which would affect si_code. */
cs->exception_index = EXCP_DMP;
cpu->env.cr[CR_IOR] = address;
cpu_loop_exit_restore(cs, retaddr);
}
#else
static hppa_tlb_entry *hppa_find_tlb(CPUHPPAState *env, vaddr addr)
{
int i;
@ -392,4 +378,3 @@ int hppa_artype_for_page(CPUHPPAState *env, target_ulong vaddr)
hppa_tlb_entry *ent = hppa_find_tlb(env, vaddr);
return ent ? ent->ar_type : -1;
}
#endif /* CONFIG_USER_ONLY */