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qapi: replace if condition list with dict {'all': [...]}
Replace the simple list sugar form with a recursive structure that will accept other operators in the following commits (all, any or not). Signed-off-by: Marc-André Lureau <marcandre.lureau@redhat.com> Message-Id: <20210804083105.97531-7-marcandre.lureau@redhat.com> Reviewed-by: Markus Armbruster <armbru@redhat.com> [Accidental code motion undone. Degenerate :forms: comment dropped. Helper _check_if() moved. Error messages tweaked. ui.json updated. Accidental changes to qapi-schema-test.json dropped.] Signed-off-by: Markus Armbruster <armbru@redhat.com>
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27 changed files with 143 additions and 88 deletions
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@ -13,7 +13,8 @@
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import re
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from typing import (
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List,
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Any,
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Dict,
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Match,
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Optional,
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Union,
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@ -199,17 +200,29 @@ def guardend(name: str) -> str:
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name=c_fname(name).upper())
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def cgen_ifcond(ifcond: Union[str, List[str]]) -> str:
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def cgen_ifcond(ifcond: Union[str, Dict[str, Any]]) -> str:
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if not ifcond:
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return ''
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return '(' + ') && ('.join(ifcond) + ')'
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if isinstance(ifcond, str):
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return ifcond
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oper, operands = next(iter(ifcond.items()))
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oper = {'all': '&&'}[oper]
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operands = [cgen_ifcond(o) for o in operands]
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return '(' + (') ' + oper + ' (').join(operands) + ')'
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def docgen_ifcond(ifcond: Union[str, List[str]]) -> str:
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def docgen_ifcond(ifcond: Union[str, Dict[str, Any]]) -> str:
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# TODO Doc generated for conditions needs polish
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if not ifcond:
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return ''
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return ' and '.join(ifcond)
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if isinstance(ifcond, str):
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return ifcond
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oper, operands = next(iter(ifcond.items()))
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oper = {'all': ' and '}[oper]
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operands = [docgen_ifcond(o) for o in operands]
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return '(' + oper.join(operands) + ')'
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def gen_if(cond: str) -> str:
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