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Monitor: Return before exiting with 'quit'

Browse source 
The 'quit' Monitor command (implemented by do_quit()) calls
exit() directly, this is problematic under QMP because QEMU
exits before having a chance to send the ok response.

Clients don't know if QEMU exited because of a problem or
because the 'quit' command has been executed.

This commit fixes that by moving the exit() call to the main
loop, so that do_quit() requests the system to quit, instead
of calling exit() directly.

Signed-off-by: Luiz Capitulino <lcapitulino@redhat.com>
This commit is contained in:
Luiz Capitulino 2010-04-06 18:55:54 -03:00
parent 04f8c053cc
commit 0e8d2b5575
3 changed files with 22 additions and 1 deletions
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18
vl.c
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@ -1697,6 +1697,7 @@ static int shutdown_requested;
static int powerdown_requested;
int debug_requested;
int vmstop_requested;
static int exit_requested;
int qemu_shutdown_requested(void)
{
@ -1719,6 +1720,12 @@ int qemu_powerdown_requested(void)
return r;
}
int qemu_exit_requested(void)
{
/* just return it, we'll exit() anyway */
return exit_requested;
}
static int qemu_debug_requested(void)
{
int r = debug_requested;
@ -1789,6 +1796,12 @@ void qemu_system_powerdown_request(void)
qemu_notify_event();
}
void qemu_system_exit_request(void)
{
exit_requested = 1;
qemu_notify_event();
}
#ifdef _WIN32
static void host_main_loop_wait(int *timeout)
{
@ -1925,6 +1938,8 @@ static int vm_can_run(void)
return 0;
if (debug_requested)
return 0;
if (exit_requested)
return 0;
return 1;
}
@ -1977,6 +1992,9 @@ static void main_loop(void)
if ((r = qemu_vmstop_requested())) {
vm_stop(r);
}
if (qemu_exit_requested()) {
exit(0);
}
}
pause_all_vcpus();
}