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memory: split memory_region_from_host from qemu_ram_addr_from_host

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Move the old qemu_ram_addr_from_host to memory_region_from_host and
make it return an offset within the region.  For qemu_ram_addr_from_host
return the ram_addr_t directly, similar to what it was before
commit 1b5ec23 ("memory: return MemoryRegion from qemu_ram_addr_from_host",
2013-07-04).

Reviewed-by: Marc-André Lureau <marcandre.lureau@gmail.com>
Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
This commit is contained in:
Paolo Bonzini 2016-03-25 12:55:08 +01:00
parent f615f39616
commit 07bdaa4196
7 changed files with 51 additions and 20 deletions
Download patch file Download diff file Expand all files Collapse all files

6
target-i386/kvm.c
View file

@ -411,7 +411,8 @@ int kvm_arch_on_sigbus_vcpu(CPUState *c, int code, void *addr)
if ((env->mcg_cap & MCG_SER_P) && addr
&& (code == BUS_MCEERR_AR || code == BUS_MCEERR_AO)) {
if (qemu_ram_addr_from_host(addr, &ram_addr) == NULL ||
ram_addr = qemu_ram_addr_from_host(addr);
if (ram_addr == RAM_ADDR_INVALID ||
!kvm_physical_memory_addr_from_host(c->kvm_state, addr, &paddr)) {
fprintf(stderr, "Hardware memory error for memory used by "
"QEMU itself instead of guest system!\n");
@ -445,7 +446,8 @@ int kvm_arch_on_sigbus(int code, void *addr)
hwaddr paddr;
/* Hope we are lucky for AO MCE */
if (qemu_ram_addr_from_host(addr, &ram_addr) == NULL ||
ram_addr = qemu_ram_addr_from_host(addr);
if (ram_addr == RAM_ADDR_INVALID ||
!kvm_physical_memory_addr_from_host(first_cpu->kvm_state,
addr, &paddr)) {
fprintf(stderr, "Hardware memory error for memory used by "