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Correctly write matrices and the cura version metadata tag

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Fixes an issue with invalid 3MF files
This commit is contained in:
Arjen Hiemstra 2017-01-23 17:38:15 +01:00
parent 3d58bd4d49
commit e9db6498ba
1 changed files with 5 additions and 4 deletions
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9
plugins/3MFWriter/ThreeMFWriter.py
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@ -44,7 +44,7 @@ class ThreeMFWriter(MeshWriter):
result += str(matrix._data[2,2]) + " " result += str(matrix._data[2,2]) + " "
result += str(matrix._data[0,3]) + " " result += str(matrix._data[0,3]) + " "
result += str(matrix._data[1,3]) + " " result += str(matrix._data[1,3]) + " "
result += str(matrix._data[2,3]) + " " result += str(matrix._data[2,3])
return result return result
## Should we store the archive ## Should we store the archive
@ -78,10 +78,11 @@ class ThreeMFWriter(MeshWriter):
model_relation_element = ET.SubElement(relations_element, "Relationship", Target = "/3D/3dmodel.model", Id = "rel0", Type = "http://schemas.microsoft.com/3dmanufacturing/2013/01/3dmodel") model_relation_element = ET.SubElement(relations_element, "Relationship", Target = "/3D/3dmodel.model", Id = "rel0", Type = "http://schemas.microsoft.com/3dmanufacturing/2013/01/3dmodel")
model = ET.Element("model", unit = "millimeter", xmlns = self._namespaces["3mf"]) model = ET.Element("model", unit = "millimeter", xmlns = self._namespaces["3mf"])
model.set("xmlns:cura", self._namespaces["cura"])
# Add the version of Cura this was created with. As "CuraVersion" is not a recognised metadata name # Add the version of Cura this was created with. Since there is no "version" or similar metadata name we need
# by 3mf itself, we place it in our own namespace. # to prefix it with the cura namespace, as specified by the 3MF specification.
version_metadata = ET.SubElement(model, "metadata", xmlns = self._namespaces["cura"], name = "CuraVersion") version_metadata = ET.SubElement(model, "metadata", name = "cura:version")
version_metadata.text = Application.getInstance().getVersion() version_metadata.text = Application.getInstance().getVersion()
resources = ET.SubElement(model, "resources") resources = ET.SubElement(model, "resources")